通达信阳光突破公式副图源码

[复制链接]
查看127 | 回复0 | 2021-8-18 18:16:41 | 显示全部楼层 |阅读模式

以下是通达信阳光突破公式副图源码(无源码的请下载附件导入)

阳光突破 源码

 

突破12:=REF(COUNT(C/O>1.06 OR C/REF(C,1)>1.099,6)>=1  AND ((CLOSE-REF(CLOSE,3))/REF(CLOSE,3))*100<=-5.6,1) AND REF(C/REF(C,1)<1.099,3) AND C/O>O/L AND C>O  AND C>REF(O,1) AND REF(C<O,3) AND REF(C<O AND H/O>1.005,2) AND REF(C<O AND H/O>1.003,1) ;

 

突破23:=

REF(COUNT(C/REF(C,1)>1.099,3)<1,1)    AND REF(O,2)<REF(H,3) 

AND C/O>1.037  AND C>=REF(C,3) AND C>REF(C,1) AND C>REF(C,2)  AND C/O>REF(C/O,1)

AND (REF(O,2)<REF(H,3) AND REF(O,1)<=REF(H,2) AND REF(O,1)<=REF(H,2)  AND (REF(C/O>1.0267 AND C/REF(C,1)>1.0198,3) AND REF(C/O,3)>REF(C/O,4) AND H>REF(H,3)  AND REF((C>O AND C/O<1.04) OR O<=REF(C,1),2) AND REF(C>O AND (H/C>O/L OR C/O>O/L),1) ) );

 

突破24:=

REF(COUNT(C/REF(C,1)>1.099,3)<1,1)    AND REF(O,2)<REF(H,3) 

AND C/O>1.037  AND C>=REF(C,3) AND C>REF(C,1) AND C>REF(C,2)  AND C/O>REF(C/O,1)

AND (  (REF(O,2)<REF(H,3) AND REF(O,1)<=REF(H,2) AND REF(O,1)<=REF(H,2)  AND REF(C/O>1.0267 AND C/REF(C,1)>1.0198,4)  AND REF(C/O,3)<REF(C/O,4) AND REF(C/O<1.04 OR O<REF(C,1),3) )  );

 

突破25:=

REF(COUNT(C/REF(C,1)>1.099,3)<1,1)    AND REF(O,2)<REF(H,3) 

AND C/O>1.037  AND C>=REF(C,3) AND C>REF(C,1) AND C>REF(C,2)  AND C/O>REF(C/O,1)

AND ( (REF(L,2)<REF(H,3) AND REF(C/O>1.0267 AND C/REF(C,1)>1.027,5)  AND (REF(C>O,3) OR (REF(C<O,3) AND C>REF(O,3))) AND REF(C/O,4)<REF(C/O,5) AND REF(C/O<1.04,4)  ) );

 

突破26:=

REF(COUNT(C/REF(C,1)>1.099,3)<1,1)    AND REF(O,2)<REF(H,3) 

AND C/O>1.037  AND C>=REF(C,3) AND C>REF(C,1) AND C>REF(C,2)  AND C/O>REF(C/O,1)

AND (  (REF(L,2)<REF(H,3) AND REF(C/O>1.0267 AND C/REF(C,1)>1.027,6) AND C>REF(C,4) AND (REF(C>O,4) OR (REF(C<O,4) AND C>REF(O,4)))  AND REF(C/O,5)<REF(C/O,6) AND REF(C/O<1.04,5)  ) );

突破1:突破12 OR 突破23;

突破2:突破24;

突破3:突破25 OR 突破26;

DRAWICON(突破23 AND REF(COUNT(C>O,2)=2,1),0.5,24);

DRAWICON(突破24 AND REF(COUNT(C<=O,3)=3,1),0.9,26);

 

回复

使用道具 举报

您需要登录后才可以回帖 登录 | 立即注册

本版积分规则